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    • I learned this but forgot about it, it's actually not that hard
      AnasKhan 17 aug
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    • Here you go boys
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    • Arcaeca 17 aug
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    • johanmoua 17 aug
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    • An yall thought you wouldnt use that shit in real life
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    • -1/3(2)^3 -1/2(2)^2 +2(2) = -8/27-1+4 = ~2.7 -1/3(-1)^3 -1/2(-1)^2 +2(-1) = 1/27+1-2 = ~(-0.96) 2.7-(-0.96) = ~3.66 Approximate answer: 3.66 I got the answer to the integral to be -11/3x^3-1/2x^2+2x
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    • Integrating ( 2 - x^2 + x ) from x=-1 to x=2 gives the area of 4.5 units
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    • Solved
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    • BIeu 17 aug
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    • Me about to start calculus: how do I do that again?
      mysterioh 17 aug
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    • Oh integrals
      ddog042 20 aug
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    • It's 4.5 units squared
      Hitman_ 17 aug
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    • Find the intercepts, determine which graph is above the other, then do the integral of the top function minus the bottom function from intercept a to intercept b
      Gekko 17 aug
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    • Who here took calculus AB?
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    • The answer is 4.5 guys. Take the integral of 2-x^2 from -1 to 2 and subtract the integral of -x from -1 to 2 and it's 3- (-1.5) so 4.5 is the answer.
      rehmanpa 17 aug
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    • Just take the integral of the first minus the second bounded at the interception points
      guzze 17 aug
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    • 4 Copy FacebookPinterestTwitterEmail {{ shortRepliesCount }}
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    • SmartPHOWNED
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    • Basic integrals
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    • I know this is a joke, but on the real dudes who try and get other dudes to not hit up his chick like she wasnt involved make no sense to me. Why would you defend a hoe who's fucking around behind your back?
      Age_ 19 aug
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    • 3 Copy FacebookPinterestTwitterEmail {{ shortRepliesCount }}
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    • In case anyone was wondering the answer is 4.5
      Jstebs 18 aug
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    • 3 Copy FacebookPinterestTwitterEmail {{ shortRepliesCount }}
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    • Fucking 9/2. Takes half a damn minute in a TI-84
      Ashraven 18 aug
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    • 3 Copy FacebookPinterestTwitterEmail {{ shortRepliesCount }}
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    • First you have to find the two intersection points to use as the boundary conditions of the integral. Then you integrate the difference between the higher values function and the Lower values function - assuming both are completely positive valued functions in the region in question.
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    • content not available more
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    • Difference of 2 integrals my dudes
      Orangei 17 aug
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    • Baby Calculus
      Tim_Rus 17 aug
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    • I legit just learned this in Calculus 3
      DJ_JK 17 aug
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    • Damn I for the equation but its definitely less than 1 and more than 1/2. I'm no youtuber but I'm bored as fuck, so If this 50 likes I'll solve it.
      Maloce 17 aug
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    • This is actually pretty easy. It gets hard when you have to find the volume of the region when it’s revolved around something
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    • It’s 4.5
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    • 3 Copy FacebookPinterestTwitterEmail {{ shortRepliesCount }}
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    • Subtract the integral of both functions using the intersection points as the upper and lower limits.
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    • Only real BC calc noons know it's 5.833
      iElonMusk 17 aug
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    • Might be worth, but I believe it's 5 5/6 (~5.83)
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    • Anyone that says they know this learned this about a week ago in math class and acts like they’ll never forget it
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    • For anyone who’s scared of calculus, don’t be. This is basically the extent of calc AB. (It add more complex geometry, but same concept). This is just a single integration with bounds.
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    • Integral of (-x^2 + 2 + x) from -1 to 2 (where they intersect) the integral is -1/3x^3 + 2x + 1/2x^2 then fill in from -1 to 2 is [(-8/3 + 4 + 2) - (1/3 - 2 + 1/2)] = (-3 + 6 + 2 - 1/2) = 9/2
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    • Subtract the functions to get 2-x^2-x, then integrate with the bounds being the roots (-1 and 2). Answer is 4.5
      Hjerpower 17 aug
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    • That's actually not a hard problem
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    • i mean you just use the theorem of calculus
      Lemons_ 17 aug
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    • In terms of x or in terms of y?
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    • It would be the integral from x=-1 to x=2 of (2-x^2-(-x)) which is 2(2)-(1/3)(2^3)+(1/2)2^2-(2(-1)-(1/3)(-1^3)-(1/2)(-(-1^2))) which is 4-(8/3)+2+2-(1/3)-(1/2)=4.5
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    • Bruh said, “Damn you” like Cell in DBZ
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    • The answer is 4.5. Simple integral from -1 to 2
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    • Baskimo 17 aug
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    • He just got smartphwned
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    • Heres a problem for you, apply that bullshit to real life
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    • content not available more
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    • Take the integral, plug the limits, and add them up lol
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    • Simple integration
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    • Wya calc bc gang
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    • Traded his girl for answers on a math test...smh.
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    • Easy. It's 3
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    • Find the intersections and integrate
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    • It’s 4.5
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    • I did it my head bc Im too fuckin lazy to get a piece of paper but I'm pretty sure it's 4.5
      Annaleone 18 aug
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    • Integration really isn’t all that bad.
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    • Easy calc, just need to do an integration
      BigSir 18 aug
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    • If you text and flirt with someone else's girlfriend you're fucking retarded
      2 Copy FacebookPinterestTwitterEmail {{ shortRepliesCount }}
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    • The answer is 2
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    • Integral of (2-x^2)-(-x) from -1 to 2.
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    • ∫²-₁(2-x² + x) dx = 2x - x³/3 + x²/2 = [2(2) - (2)³/3 + (2)²/2] - [2(-1) - (-1)³/3 +(-1)²/2] = (10/3) - (-7/6) = 27/6 = 9/2
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    • U just have to use a definite integral with the bounds being the intersection points of the two lines
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    • Integral of pi times Top minus bottom squared dy
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    • We need an A and a B for the integral bitch
      remo25801 17 aug
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    • Simple integral
      2 Copy FacebookPinterestTwitterEmail {{ shortRepliesCount }}
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    • Basic calculus
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    • Its 51. I've only had general math, no algebra or calculus but I know key words and why would he request you meet him at an area? Nobody says that. Deduction: area 51.
      hawl 17 aug
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    • This is basic calculus
      KingApex 17 aug
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    • SmartphOWNED
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    • Intersection points, then take the definite integral of the parabola (if it is above the line) subtracting the definite integral of the line from it. If it's the other way around, then the parabola opens upward and you do the line first.
      Etiketi 17 aug
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    • 2 Copy FacebookPinterestTwitterEmail {{ shortRepliesCount }}
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    • This is solvable by anyone who passed high school Calc.
      2 Copy FacebookPinterestTwitterEmail {{ shortRepliesCount }}
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    • 4.5 square units
      Ry_Maho_5 17 aug
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    • Integral of top line minus integral of bottom line and a set range. Once that is done, plug the range in “x” and you get the answer.
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    • f(x) = 2 - x^2, g(x) = -x. Find where f(x) = g(x). x^2 - x - 2 = 0, x = (1 +- root(2, 1 + 8)) / 2 = {2, -1}. Now to make life easier, we'll shift everything up so the region is above the x-axis (g(2) = f(2) = -2, so we'll shift up by 2). Now we'll find the (relevant) area under f(x), and...
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    • I wish it was like this but damn Chinese dude keep solving my equations
      2 Copy FacebookPinterestTwitterEmail {{ shortRepliesCount }}
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    • That’s just integral calculus. I’d do it rn but I don’t have a pencil and paper
      _Nadiki_ 17 aug
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    • Jesus I took up to College Calculus II and I forgot how to do that
      Hayley512 17 aug
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    • Take the integrals of both functions with the intersections of the two functions as the bounds to find the area in between.
      Oregonian 17 aug
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    • 2 Copy FacebookPinterestTwitterEmail {{ shortRepliesCount }}
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    • The thing is the girl should make that decision if you need to tell boys to stop texting her she a thot
      Spyro_yo 17 aug
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    • its 9/2
      tadders 17 aug
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    • Calculus noons rise up
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    • 4.5 square units
      Manda_O 17 aug
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    • Owo, calculus noon
      Mitchem12 17 aug
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    • Cuz theres nothing like math to get rid of guys fucking your girlfriend
      2 Copy FacebookPinterestTwitterEmail {{ shortRepliesCount }}
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    • HybridD 17 aug
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    • Funny. But people who actually get upset over a guy having a simple platonic conversation with their significant other are retarded
      2 Copy FacebookPinterestTwitterEmail {{ shortRepliesCount }}
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    • It's really not that hard if you know basic calculus
      2 Copy FacebookPinterestTwitterEmail {{ shortRepliesCount }}
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    • Net Signed Area = ∫ (2 - x^2 - sqrt(x))dx with some limits of integration where the functions fucking intersect
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    • hahaha that guy has truly been smartphOWNED! I’m going to share this post with Debby, I’m sure she’ll love it! Thanks for posting this, Karen! 😄😄 Say hi to the kids for me!!
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    • Graph the functions, find which one is on top and the other on the bottom, set them equal to get the bounds, integrate.
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    • Use ya boy, the A N T I D E R I V A T I V E
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